-3x^2+33x-72=0

Solution for -3x^2+33x-72=0 equation:

-3x^2+33x-72=0

a = -3; b = 33; c = -72;
Δ = b2-4ac
Δ = 332-4·(-3)·(-72)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-15}{2*-3}=\frac{-48}{-6}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+15}{2*-3}=\frac{-18}{-6}
=+3
$